Wireshark *does* use that formula.
Can you give an example where you think it doesn't work?

`Note that you need to know the RTP clock sampling time (depends on
``codec)) to do the transformation from RTP timestamps to real time.
`br,
Lars Ruoff
Goran Štrok wrote:

`I do not understand how jitter is exactly calculated. I have tried with
``theese formula, but do not get the same results like Wireshark gets. Can
``anyone little explain me about this.
``
``If Si is the RTP timestamp from packet i, and Ri is the time of
`arrival in RTP timestamp units for packet i, then for two packets
i and j, D may be expressed as
D(i,j) = (Rj - Ri) - (Sj - Si) = (Rj - Sj) - (Ri - Si)
The interarrival jitter SHOULD be calculated continuously as each
data packet i is received from source SSRC_n, using this
difference D for that packet and the previous packet i-1 in order
of arrival (not necessarily in sequence), according to the formula
J(i) = J(i-1) + (|D(i-1,i)| - J(i-1))/16
Thanks.
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