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Wireshark-dev: Re: [Wireshark-dev] Absolute arrvial time of packet in wireshark

From: Vishnu Bhatt <vishnu.bhatt@xxxxxxxxxxx>
Date: Fri, 27 Jun 2014 07:23:01 +0000
Thanks for all the replies.
One more thing I would like to ask is, one thing I've noticed that the last three digits of time shown in Wireshark till nanosecs precision are always zero (for every packet).

For eg. Arrival Time: Oct 23, 2013 23:21:07.388979000 IST.

In the above case also the last three digits in .388979000 are zero, which means microsecs are multiplied with 1000 to get the nanosecs.

Can somebody please clarify more on this as to how the nanosecs obtained?

-----Original Message-----
From: wireshark-dev-bounces@xxxxxxxxxxxxx [mailto:wireshark-dev-bounces@xxxxxxxxxxxxx] On Behalf Of Guy Harris
Sent: Friday, June 27, 2014 12:34 AM
To: Developer support list for Wireshark
Subject: Re: [Wireshark-dev] Absolute arrvial time of packet in wireshark


On Jun 26, 2014, at 7:31 AM, Vishnu Bhatt <vishnu.bhatt@xxxxxxxxxxx> wrote:

> Thanks for the reply. But I am talking of the following time:

That *is* the time that Wireshark gets from libpcap/WinPcap.

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