Hi,
I think http://www.wireshark.org/faq.html#q1.9 basically covers it.
But maybe the title could be better.
Thanx,
Jaap
Rob Meades wrote:
Hokay, so a dissector links with GPL code and must therefore be provided
as source. Might be worth adding this as a note to the FAQ, whoever
controls it, just to make it clear.
Thanks!
Rob
-----Original Message-----
From: wireshark-dev-bounces@xxxxxxxxxxxxx
[mailto:wireshark-dev-bounces@xxxxxxxxxxxxx] On Behalf Of Luis EG
Ontanon
Sent: 18 December 2008 15:49
To: Developer support list for Wireshark
Subject: Re: [Wireshark-dev] Wireshark licence terms and dissectors
http://www.gnu.org/licenses/old-licenses/gpl-2.0-faq.html#LinkingWithGPL
On Thu, Dec 18, 2008 at 3:59 PM, Rob Meades <Rob.Meades@xxxxxxxxxx>
wrote:
Apologies if this is already known, but I couldn't find the answer in
the FAQ.
We have created a dissector for Wireshark and would like to provide it
to our customers. Is a dissector considered a part of Wireshark from
the point of view of the GPL license? In other words, are we required
to give the source code for the dissector to our customers?
Thanks in advance for any pointers.
Rob
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